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Consider the circuit attached. If v = 130 V, how is the node-voltage method applied to find vo = 32.5 volts?
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- Discussion For the circuit below complete the table R 5 Ω 10 V 60 Hz 100 μF R Total 10+j0 10 0° Volts 68.623m+ j364.06m Amps 370.5m Z 79.325° 5+ j0 0- j26.5258 5 - j26.5258 Ohms 52 0° 26.5258 Z-90° 26.993 Z-79.325° NDiscussion For the circuit below complete the table R 5 Ω 10 V 60 Hz 100 μF R Total 10+j0 10 0° Volts 68.623m +j364.06m Amps 370.5m Z 79.325° 5+ j0 0- j26.5258 5 - j26.5258 Ohms 520° 26.5258 -90° 26.993 Z-79.325°No. 1 2 3 4 5 6 7 8 9 10 Mnemonics MOV A, # 0A9h RL A RL A SWAP A CLR C RRC A SWAP A CLR C RRC A SWAP A Operation
- نقطتان )2( For the circuit in figure below, the * :value of R1 is 2 A R1 R2 R3 17.50 140 V 15 Q O 44 Q O 23.8 Q O 100 ΟDraw Vout versus Vin for the given values below. Vin V₂ V₁ + V V V www 5 ΚΩ Vout Student numbers from 190207066 up to 200207084 V₁=5 V, V₂ 9 V, V₁= 15 V, V_= -15 V, V= 11 V, Output High =14 V Output Low = 11 V (including) Vin 13xSin tDraw a small signal AC equivalent circuit. Assume V=0 +20V Rc1 2k2 Cc 10µF R1 100k2 R Rc2 3k2 2k2 Vo 4µF Zo B = 100 Rs 1k2 R2 20k2 RE 5k2 CE 70µF Vs
- Find the Ceg for the circuit given below: C C C eq C C O 10 O 2.5C O 20 O 1.5CInductive Circuits Fill in all the missing values. Refer to the following formulas: XL=2fLL=XL2ff=XL2L Inductance (H) Frequency (Hz) Inductive Reactance ( ) 1.2 60 0.085 213.628 1000 4712.389 0.65 600 3.6 678.584 25 411.459 0.5 60 0.85 6408.849 20 201.062 0.45 400 4.8 2412.743 1000 40.841Discussion For the circuit below complete the table R 5Ω 10 V 60 Hz 100 µF R C Total 10 + j0 V Volts 10 Z0° 68.623m + j364.06m Amps 370.5m Z 79.325° 5+ j0 52 0° 5 - j26.5258 26.993 Z-79.325° 0 - j26.5258 Ohms 26.5258 Z-90°
- use these values: Vs=130 R=280Using source transformation, calculate the value of I3 (in amps). (disregard the direction or polarity, consider the magnitude only) R30 R20 R360 120R V E 9V E 20 VZVO A VM ll l Ciassroo docs.google.com a Q1 For the following circuit diagram, 1 is .......... 50 15 V 12V 40 50 I2 70 60 90 12 a 4 A 1 O -1 احمد عصام احمد 8:00- äc lul 21.04.20 O D