Please answer Consider the following reaction at constant P. Use theinformation here to determine the value of ASurr at35°C. Predict whether or not this reaction will bespontaneous at this temperature.CH4(8) + 202(8) -> CO2{3) + 2H2O(1)AH°nn-890.4 kJASsurr = +25.44 kJ/K, reaction is spontaneous%3DASsurr = -25.44 kJ/K, reaction is spontaneous%3DO ASsurr = -2.23 kJ/K, reaction is non-spontaneous= + 2.23 kJ/K, reaction is spontaneousASsurrASsurr =+2.23 kJ/K, it is not possible to predict thespontaneity of this reaction without more information.%3DASurr +25.44 kJ/K, it is not possible to predict thespontaneity of this reaction without more information.ASaurr-2.23 kJ/K, it is not possible to predict thespontaneity of this reaction without more information.O ASurr-25.44 kJ/K, it is not possible to predict thespontaneity of this reaction without more information.

The reaction taking place is given as, => CH4 (g) + 2 O2 (g) -----> CO2 (g) + 2 H2O (l)…

Consider the following reaction at constant P. Use the information here to determine the value of ASurr at 35°C. Predict whether or not this reaction will be spontaneous at this temperature. CH4(8) + 202(s) -> CO2(3) + 2H2O(1) AH nn -890.4 kJ O ASsurr = +25.44 kJ/K, reaction is spontaneous %3D ASurr = -25.44 kJ/K, reaction is spontaneous %3D O ASsurr = -2.23 kJ/K, reaction is non-spontaneous %3D ASqurr = + 2.23 kJ/K, reaction is spontaneous O ASsurr = +2.23 kJ/K, it is not possible to predict the spontaneity of this reaction without more information. %3D O ASurr+25.44 kJ/K, it is not possible to predict the spontaneity of this reaction without more information. ASsurr - -2.23 kJ/K, it is not possible to predict the spontaneity of this reaction without more information. O ASsurr-25.44 kJ/K, it is not possible to predict the spontaneity of this reaction without more information.

Consider the following reaction at constant P. Use the information here to determine the value of ASurr at 35°C. Predict whether or not this reaction will be spontaneous at this temperature. CH4(8) + 202(s) -> CO2(3) + 2H2O(1) AH nn -890.4 kJ O ASsurr = +25.44 kJ/K, reaction is spontaneous %3D ASurr = -25.44 kJ/K, reaction is spontaneous %3D O ASsurr = -2.23 kJ/K, reaction is non-spontaneous %3D ASqurr = + 2.23 kJ/K, reaction is spontaneous O ASsurr = +2.23 kJ/K, it is not possible to predict the spontaneity of this reaction without more information. %3D O ASurr+25.44 kJ/K, it is not possible to predict the spontaneity of this reaction without more information. ASsurr - -2.23 kJ/K, it is not possible to predict the spontaneity of this reaction without more information. O ASsurr-25.44 kJ/K, it is not possible to predict the spontaneity of this reaction without more information.

Chemistry for Engineering Students

4th Edition

ISBN:9781337398909

Author:Lawrence S. Brown, Tom Holme

Publisher:Lawrence S. Brown, Tom Holme

Chapter10: Entropy And The Second Law Of Thermodynamics

Section: Chapter Questions

Problem 10.80PAE

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Similar questions

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