Consider the titration of 100.0 mL of0.250 M anilinium chloride, C6H5NH3CI,(K₂ for anilinium ion = 2.6 x 10-4) witha0.500 M NaOH at 25 °C.Calculate the pH when 15.00 mL oftitrant have been added.

Given,molarity of anilinium chloride, C6H5NH3Cl = 0.250 MVolume of C6H5NH3Cl = 100.0 mLKa of…

Consider the titration of 100.0 mL of 0.250 M anilinium chloride, C6H5NH³CI, (K₂ for anilinium ion = 2.6 x 10-4) with 0.500 M NaOH at 25 °C. Calculate the pH when 15.00 mL of titrant have been added.

Consider the titration of 100.0 mL of 0.250 M anilinium chloride, C6H5NH³CI, (K₂ for anilinium ion = 2.6 x 10-4) with 0.500 M NaOH at 25 °C. Calculate the pH when 15.00 mL of titrant have been added.

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter14: Principles Of Neutralization Titrations

Section: Chapter Questions

Problem 14.7QAP

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Concept explainers

Acid Base Titration

An acid-base titration is the method of quantitative analysis for determining the concentration of an acid and base by exactly neutralizing it with a standard solution of base or acid having known concentration.

Question

Consider the titration of 100.0 mL of
0.250 M anilinium chloride, C6H5NH3CI,
(K₂ for anilinium ion = 2.6 x 10-4) with
a
0.500 M NaOH at 25 °C.
Calculate the pH when 15.00 mL of
titrant have been added.

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