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Find Fourier transform for: rect(t – 2). cos(500t) Select one: O a. F[rect(t - 2). cos(500t)] = le 23(w-500). sinc W-500 e-2j(w+500). sinc %3D w+500 O b. F[rect(t - 2).cos(500t)] = S00 je 2[sinc",2 + sinc w-2 O c. F[rect(t – 2). cos(500t)] = e* [sinc", + sinc"] 500 juw w-2 %3D O d. Frect(t- 2). cos(500t)] = le+2j(w-500). sinc" 500 + e+2j(w+500) sinc "+500 2. %3D O e. F(rect(t - 2). cos(500t) = e+3j (sinc" w-500 + sinc +500 O f. F(rect(t - 2). cos(500t)] = (sinc"-502 + sinc +498 %3D 2. g. F(rect(t- 2). cos(5004)] = e 3j" [sinc 4-500 + sinc +500

Find Fourier transform for: rect(t – 2). cos(500t) Select one: O a. F[rect(t - 2). cos(500t)] = le 23(w-500). sinc W-500 e-2j(w+500). sinc %3D w+500 O b. F[rect(t - 2).cos(500t)] = S00 je 2[sinc",2 + sinc w-2 O c. F[rect(t – 2). cos(500t)] = e* [sinc", + sinc"] 500 juw w-2 %3D O d. Frect(t- 2). cos(500t)] = le+2j(w-500). sinc" 500 + e+2j(w+500) sinc "+500 2. %3D O e. F(rect(t - 2). cos(500t) = e+3j (sinc" w-500 + sinc +500 O f. F(rect(t - 2). cos(500t)] = (sinc"-502 + sinc +498 %3D 2. g. F(rect(t- 2). cos(5004)] = e 3j" [sinc 4-500 + sinc +500

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Find Fourier transform for: rect(t – 2).cos(500t) Select one: O a. F(rect(t- 2). cos(500t)] = He-2j(w-500). sinc" +e 2}{w+500) sinc500 %3D w-500 -500 jw O b. F(rect(t – 2). cos(500t)] = ! 2 sinc", + sinc"] w+2 O . F(rect(t - 2).cos(500t)] = e500ju [sinc", + sinc" O d. Frect(t- 2). cos(500t)] = (e+23(w-500) sinc -500 +e+2j(w+500). sinc"+500 O e. F[rect(t – 2). cos(500t)] =e*2j [sinc ロ-500 + sinc"500 %3D O f. Frect(t - 2). cos(500t)] = (sinc w-502 + sinc w+498 g. F(rect(t-2). cos(5004) =e-2j" [sinc" to-500 + sinc"t500 %3D 2
Transcribed Image Text:Find Fourier transform for: rect(t – 2).cos(500t) Select one: O a. F(rect(t- 2). cos(500t)] = He-2j(w-500). sinc" +e 2}{w+500) sinc500 %3D w-500 -500 jw O b. F(rect(t – 2). cos(500t)] = ! 2 sinc", + sinc"] w+2 O . F(rect(t - 2).cos(500t)] = e500ju [sinc", + sinc" O d. Frect(t- 2). cos(500t)] = (e+23(w-500) sinc -500 +e+2j(w+500). sinc"+500 O e. F[rect(t – 2). cos(500t)] =e*2j [sinc ロ-500 + sinc"500 %3D O f. Frect(t - 2). cos(500t)] = (sinc w-502 + sinc w+498 g. F(rect(t-2). cos(5004) =e-2j" [sinc" to-500 + sinc"t500 %3D 2
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