Find(i)(iii) 11011.110zx1001.0011z11010011.111102+10101011.1000112(ii)101111.112 -1100.1012(IV) 100111010.102 by1101zRepresent(-52)1oin

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Answered: Find (ii)101111.112 -1100.1012 (IV)…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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VIII) Find (i) 11010101.11102 + 10101011.1010112 (ii) 1010101.112 – 1100.1012(iii) 110001.1102 x 1011.0012 (iv) 1011011010.102 by 11012
VIII) Find (i) (iii) 11011.1102 x 1001.00112 (ii) 101111.112 - 1100.1012 (iv) 100111010.102 by 11012 11010011.110102 + 10101011.1010112
Q1/Find( (90)10/(36)8)* (F1)16+(1100111)2=( )Gray O 1000101100 O 1010100111 O None of them O 110100111 O 100101100
2)Convert 11011010100100012 to hexadecimal. A)895B B)CA11 C)53AC1 D)DA91
Q1. Convert following numbers in given radix system: a. (697)10 into Octal and Hexa decimal b. (2D9)16 into Decimal and Octal Q2. Using two's complement representation, solve: a. 101110001 – 1111111001 b. 1010101010 – 1010010101 Q3. Perform following arithmetic operations: a. (6767)10 + (3592)10 using BCD b. (C7C)16 - (B0E)16 using 16's complement Q4. A code 1011011 needs to be sent to the receiver. Using, hamming code find out the code- word and the mechanism to check the corrected data when error occurred at 4th bit. (Assumptions: Right to Left with Odd Parity) Q5. (a) Convert the following logic gate circuit into a Boolean expression, writing Boolean sub-expressions next to each gate output in the diagram: A (b) Realise Ex-OR gate using universal gate? Q6. Implement and simplify f (A, B, C, D) = E(1,3,5,8,9,11,13,15) using K-map?
7. Add the following binary mumbers: 10010 1011101 10011 +1100 + 1000000 + 1111101 10011001 11000011 1001100 100111 + 101111 + 1100101
c) Do the following binary subtraction: 111001101.00111- 010000010.10110
t of For R1-47 0, R2=72 Q, R3=104 Q, V1=6 V, 1=40 A & K1=4.5, use the principle of superposition to find : R2 KIV, R3 V1 I1 R1 V01 (in volt) due to V1 only= a. 0 b. -0.028190603132289 C. -0.018793735421526 d. -0.0093968677107631
Solve the following numbers: (a) (1100010.001 – 111111.101)2 (b) (433.22 + 54.30)6
Find the absolute and relative error of the following. a)The approximate value of e is used as 2.718. Calculate the absolute error and the relative error margin accordingly. b) P=3.1415927 and this value is given as an approximate result of p=3.1416. Calculate the absolute error and relative error margin accordingly.
Draw the graphs of the Manchester, differential Manchester, NRZ-I and NRZ-L schemes for each of the following data streams: 00110011 10101010
1.2 Convert to octal. Convert to hexadecimal. Then convert both of your answers to decimal, and verify that they are the same. 111010110001.011, (b) 10110011101.112

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Find (ii)101111.112 -1100.1012 (IV) 100111010.102 by1101z 11010011.111102+10101011.1000112 (iii) 11011.110zx1001.0011z