int main() ( int counter, first, last, next; first = 1; last = 2; for (counter = first; counter <= last; counter++) cout << "\n next counter * counter; cout <« " ww " « counter; " « next; counter = first; while (counter <= last)( cout <« "\n " « counter; next = counter * counter; cout <« " " « next; counter++; counter = first; do ( cout <« "\n " « counter; next = counter * counter; cout << " " « next; ww counter++; } while (counter < last); }

int main() ( int counter, first, last, next; first = 1; last = 2; for (counter = first; counter <= last; counter++) cout << "\n next counter * counter; cout <« " ww " « counter; " « next; counter = first; while (counter <= last)( cout <« "\n " « counter; next = counter * counter; cout <« " " « next; counter++; counter = first; do ( cout <« "\n " « counter; next = counter * counter; cout << " " « next; ww counter++; } while (counter < last); }

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

See similar textbooks

Similar questions

int func(int a, int b) { return (a
PLEASE HELP ME! ? Maximize and use alternative method to this code! package com.btech.pf101; import java.io.bufferedreader; import java.io.inputstreamreader; import java.util.calendar; import java.util.date; public class pawnshopcode { private static final bufferedreader br = new bufferedreader(new inputstreamreader(system.in)); private static string name; private static int age; private static string address; private static string contactno; private static int itemtype; private static string itemtypename; private static final int itemtype_gagdet = 1; private static final int itemtype_jewelry = 2; private static final int itemtype_musicinstrument = 3; private static final int itemtype_homeequipment = 4; private static final int itemtype_landtitle = 5; private static string itemdescription; private static int periodtype; private static string periodtypename; private static final int periodtype_days = 1; private…
int sum = 0; for (int i 0; i < 5; i++){ sum += i; } cout << sum;
void fact(int num) { int k,f=1; for (k=1;k<=num; k++) f=f*k; cout<< f; int main() { int arri[3]={3,2,1} ; for(int i=0;i<3;i++) fact(arri[i]); } 261 O 621 O 7 462
int calculatepower (int x, int y){ if (y > 0) return x* else return 1; int main (){ int num, pwr; cout > num; cout > pwr; cout <« "Number "<
void exchangeByValue (int x, int y) { printf ("\n\nOriginal x and y received: $d $d", x, y); int temp; temp =x; x=y; y=temp; printf("\nNew: id $d", x, y): } void exchangeByRef (int *x, int *y) { printf ("\n\nOriginal x and y received: $d $d", *x, *y); int temp; temp = *x; *x = *y; *y = temp; printf ("\nNew: id $d", *x, *y); } а. Show the output b. Trace the output (show the tracing using drawing). Explain your answer if necessary.
Match the C-function on the left to the Intel assemble function on the right. W: cmpl $4 movl %edi , %edi jmp .L4(,%rdi,8) %edi .L3: movl $17, %eax ret .15: movl $3, %eax int A ( int x , int y) { int a ; if ( x == 0 ) else i f ( x == 1 ) a = 3 ; else i f ( x == 2 ) a = 2 0 ; else i f ( x == 3 ) a = 2 ; else i f ( x == 4 ) a = 1 ; ret .L6: a = 17; movl $20, %eax ret .L7: movl $2, %eax ret else a = 0; .L8: return a ; movl $1, %eax .L2: ret . section .rodata . L4: .quad .L3 .quad .L5 .quad .L6 .quad .L7 .quad .L8 X: testl %edi, %edi je cmpl je cmpl je стр1 je cmpl .L16 $1, %edi .L17 $2, %edi .L18 $3, %edi int B (int x, int y) { int a; switch (x) { .L19 $4, %edi %al movzbl %al, %eax case 0: a = 17; break; sete break; case 1: a = 3; case 2: a = 20; break; case 3: a = 2; break; case 4: a = 1; a = 0; } return a; ret .L16: break; movl $17, %eax ret .L17: movl $3, %eax } ret .L18: movl $20, %eax ret .L19: movl ret $2, %eax
int main(){ long long int total; long long int init; scanf("%lld %lld", &total, &init); getchar(); long long int max = init; long long int min = init; int i; for (i = 0; i < total; i++) { char op1 = '0'; char op2 = '0'; long long int num1 = 0; long long int num2 = 0; scanf("%c %lld %c %lld", &op1, &num1, &op2, &num2); getchar(); long long int maxr = max; long long int minr = min; if (op1 == '+') { long long int sum = max + num1; maxr = sum; minr = sum; long long int res = min + num1; if (res > maxr) { max = res; } if (res < minr) { minr = res; } } else { long long int sum = max * num1; maxr = sum; minr = sum; long long int res = min * num1;…
Q1 function myFunc() { let a = 10; if (true) { Q3 } } let a = 5; console.log(a); Q4 console.log(a); Q2 const square = num => num * num; console.log(square(3) + 5); myFunc(); let x = 30; let y "200"; console.log(x+y); const nums = [10, 20, 8, 17]; nums.filter(e=> e > 10); console.log(nums); Q5 const nums = [30, 35, 42, 20, 15]; console.log(nums.every (num => num > 20)); January 15
void fun(int i) { do { if (i % 2 != 0) cout =1); cout << endl; } int main() { int i = 1; while (i <= 8) { fun(i); it; } cout <
mkfifo("mypipe"); if (!fork()) { fp = popen("echo 37 > mypipe", "w"); %D status = pclose(fp); } else { printf("14"); sleep(1); fp = popen("cat mypipe", "r"); fgets(buffer, buffer_size, fp); printf("%s", buffer); status = pclose(fp); %3D } Consider the above code fragment, what's the output to stdout?
Trace through the following program and show the output. Show your work for partial credit. public class Employee { private static int empID = 1111l; private String name , position; double salary; public Employee(String name) { empID ++; this.name 3 пате; } public Employee(Employee obj) { empID = obj.empĪD; пате %3D оbj.naте; position = obj.position; %3D public void empPosition(String empPosition) {position = empPosition;} public void empSalary(double empSalary) { salary = empSalary;} public String toString() { return name + " "+empID + " "+ position +" $"+salary; public void setName(String empName){ name = empName;} public static void main(String args[]) { Employee empOne = new Employee("James Smith"), empTwo; %3D empOne.empPosition("Senior Software Engineer"); етрOпе.етpSalary(1000); System.out.println(empOne); еmpTwo empTwo.empPosition("CEO"); System.out.println(empOne); System.out.println(empTwo); %3D етpОпе empOne ;