Opengl Help Programming Language: c++ I need help setting coordinate boundries for this program so the shape can't leave the Opengl window. The shape needs to stay visiable.
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I need help setting coordinate boundries for this program so the shape can't leave the Opengl window. The shape needs to stay visiable.
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- A deque data structure implements the following functions: insertFront(int); //Insert at the front insertBack(int);//Insert at the back removeFront();//Remove and print front element eraseBack();//Remove and print last element first();//print first element last();//print last element Write the output of the following sequence of operations: insertFront(3), insertBack(8), insertBack(9), insertFront(5), removeFront(), eraseBack(), first(), insertBack(7), removeFront(), last(), eraseBack().Programming: C# (C sharp) without using "array, while and furthermore advance loop"Can you fix the code please on the first picture shows the error output. // Corrected code #define _CRT_SECURE_NO_WARNINGS #include "LibraryManagement.h" #include "Books.h" #include "DigitalMedia.h" #include "LibraryConfig.h" #include #include #include #include // Include the necessary header for boolean data type // Comparison function for qsort to sort Digital Media by ID int compareDigitalMedia(const void* a, const void* b) { return ((struct DigitalMedia*)a)->id - ((struct DigitalMedia*)b)->id; } // initializing library struct Library initializeLibrary() { struct Library lib; lib.bookCount = 0; lib.ebookCount = 0; lib.digitalMediaCount = 0; // Initialize book array for (int i = 0; i < MAX_BOOK_COUNT; i++) { lib.books[i].commonAttributes.id = -1; // Set an invalid ID to mark empty slot } // Initialize ebook array for (int i = 0; i < MAX_EBOOK_COUNT; i++) { lib.ebooks[i].commonAttributes.id = -1; }…
- Tic-Tac-Toe Problem Description: Tic Tac Toe game is traditionally played on a 3x3 board berween two players x and o. A player can mark a single cell by placing a symbol in it (either an 'x'or an 'o' character). A player who manages to mark a row, column, or a diagonal completely with his symbol first wins the game. The game ends in a tie if no player manages to win after all the cells have been marked. You will design a textual version of this game, in which a human player gets to play against a computer opponent. Program Specification: In this project, you will implement a complete Tie-Tac-Toe game in a Java program. Your implementation should follow this specification. You may use one or two dimensional amay as data structure for the game board. Your program should include the following list ef methods: 1. initBoard ()- update this method This function initializes the game board. There are 9 cells represented by I or 2 dimensional armay. 2. gameBoard ()- upcdate this method This…Please modify the given code based on the directions given. #include <iostream> #include <glad/gl.h> #include <GLM/glm.hpp>#include <GLFW/glfw3.h> #include "learnopengl/shader.h" #include "cs4722/x11.h" const auto number_of_vertices = 3; const unsigned int color_loc = 1; const auto b_position = 1; static const auto background_color = cs4722::x11::gray70; auto const verts_per_triangle = 3; glm::vec4 positions0[] = { glm::vec4(-.5, .8, 0, 1), glm::vec4(-.8, .2,0, 1), glm::vec4(-.2, .2, 0, 1)};auto size0 = 4 * 4 * verts_per_triangle;auto offset0 = 0;auto bOffset0 = 0;auto color0 = cs4722::x11::medium_violet_red; glm::vec4 positions1[] = { glm::vec4(.5, .8, 0, 1), glm::vec4(.2, .2,0, 1), glm::vec4(.8, .2, 0, 1)};auto size1 = 4 * 4 * verts_per_triangle;auto offset1 = offset0 + verts_per_triangle;auto bOffset1 = bOffset0 + size0;auto color1 = cs4722::x11::slate_blue; glm::vec4 positions2[] = { glm::vec4(.5, -.2, 0, 1),…Explain the general syntax used for accessing an array component.
- classHighArrayApp { public static void main(String[] args) { intmaxSize=100;// array size HighArrayarr;// reference to array arr=newHighArray(maxSize);// create the array arr.insert(77);// insert 10 items arr.insert(99); arr.insert(44); arr.insert(55); arr.insert(22); arr.insert(88); arr.insert(11); arr.insert(00); arr.insert(66); arr.insert(33); arr.display();// display items intsearchKey=35;// search for item if(arr.find(searchKey)) System.out.println("Found " + searchKey); else System.out.println("Can’t find " + searchKey); arr.delete(00);// delete 3 items arr.delete(55); arr.delete(99); arr.display();// display items again }// end main() }// end class HighArrayApp // highArray.java // demonstrates array class with high-level interface // to run this program: C>java HighArrayApp //////////////////////////////////////////////////////////////// class HighArray { private long[] a; // ref to array a private int nElems; // number of data items…c program that coverts a txt file input1.txt and converts it into a 2d array input1.txt looks like this Spain Republic of Ireland United Kingdom Ukraine Russia United States of America China Taiwan Australia Hong Kong ItalyMUST BE WRITTEN IN C PROGRAMMING LANGUAGE CANNOT EDIT TEMPLATE IMAGE IN ANY WAY: Write a program to find and display the largest value in an integer array that is divisible by 3. For example, if the array is: 1 15 2 16 3 17 4 18 5 19 The largest number divisible by 3 is 18 On the other hand, if the array does not contain any values that are divisible by 3, the program writesNo value in the array is divisible by 3As you may see in the examples, the input consists of, firstly the size of the array, followed by the array elements. The answer is preloaded with the code to read in the array. Do not change this code. The Moodle checker expects *exactly* the output as shown. For example: Input Result 6 1 2 3 4 5 6 The largest value divisible by 3 is 6 6 1 -2 4 5 -7 8 No value in the array is divisible by 3
- В.width; } { t = B.type; w = { T.type = C.type; T.width = C.width; } T → B C В > int { B.type = integer; B.width 4; } В — foat { B.type = float; B.width = 8; } { C.type = t; C.width = w; } C - [ num] C1 = array(num. value, C1.type); { C.type C.width = num. value x C1. width; }Complete my C program: #define ROW 6#define COL6 void display(int table[][COL]){ int row, col; for(row=0;row<ROW;row++){ for(col=0;col<COL;col++) printf("%3d", table[row][col]); printf("\n"); } } (Continue code)s[0]=7;s[1]=0;s[2]=-12;s[3]=9;s[4]=10;s[5]=3;s[6]=6; the value of [s[6-s[5]]is: