The average experimental mass percent of oxygen in potassium chlorate is higher than the theoretical value. This is because some of the potassium chloride product splattered out of the crucible during the heating process. Explain this statement using an analysis of the image.TV = 39.165%EV = 40.767% Mass of original KClO3 sample=Mass of KCl residue =Mass of Oxygen released =Mass Percent of Oxygen in KC103Average Mass Percent Oxygen =-KCIO3] -Sample 1[Mass of crucible, lid +[Mass of crucible + lid] =33.745 g - 32.721 g = 1.024 g[Mass of crucible, lid + residueafter 2nd heating] -[Mass of crucible + lid] =33.314 g - 32.721 g = 0.593 gMass of original KCIO3 sample -Mass of KCI residue =1.024 g - 0.593 g = 0.431 g42.090 +39.4442Mass Percent of Oxygen (experim-Mass Percent of Oxygen (experim-ental) = Mass of Oxygen released /ental) = Mass of Oxygen releasedMass of Potassium chlorate used x Mass of Potassium chlorate used x100 = 0.431 g / 1.024 g x 100 = 100 = 0.383 g / 0.971 g x 100 =42.090 %39.444%81.534Sample 2[Mass of crucible, lid + KCIO3] -[Mass of crucible + lid] =33.692 g - 32.721 g = 0.971 g2[Mass of crucible, lid + residueafter 2nd heating] -[Mass of crucible + lid] =33.309 g - 32.721 g = 0.588 gMass of original KCIO3 sample -Mass of KCI residue=0.971 g - 0.588 g = 0.383 g= 40.767 %

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Answered: The average experimental mass percent…

Chemistry: Principles and Reactions

8th Edition

ISBN:9781305079373

Author:William L. Masterton, Cecile N. Hurley

Publisher:William L. Masterton, Cecile N. Hurley

Chapter3: Mass Relations In Chemistry; Stoichiometry

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The average experimental mass percent of oxygen in potassium chlorate is higher than the theoretical value. This is because some of the potassium chloride product splattered out of the crucible during the heating process.

Explain this statement using an analysis of the image.

TV = 39.165%

EV = 40.767%

Mass of original KClO3 sample=
Mass of KCl residue =
Mass of Oxygen released =
Mass Percent of Oxygen in KC103
Average Mass Percent Oxygen =
-KCIO3] -
Sample 1
[Mass of crucible, lid +
[Mass of crucible + lid] =
33.745 g - 32.721 g = 1.024 g
[Mass of crucible, lid + residue
after 2nd heating] -
[Mass of crucible + lid] =
33.314 g - 32.721 g = 0.593 g
Mass of original KCIO3 sample -
Mass of KCI residue =
1.024 g - 0.593 g = 0.431 g
42.090 +39.444
2
Mass Percent of Oxygen (experim-Mass Percent of Oxygen (experim-
ental) = Mass of Oxygen released /ental) = Mass of Oxygen released
Mass of Potassium chlorate used x Mass of Potassium chlorate used x
100 = 0.431 g / 1.024 g x 100 = 100 = 0.383 g / 0.971 g x 100 =
42.090 %
39.444%
81.534
Sample 2
[Mass of crucible, lid + KCIO3] -
[Mass of crucible + lid] =
33.692 g - 32.721 g = 0.971 g
2
[Mass of crucible, lid + residue
after 2nd heating] -
[Mass of crucible + lid] =
33.309 g - 32.721 g = 0.588 g
Mass of original KCIO3 sample -
Mass of KCI residue=
0.971 g - 0.588 g = 0.383 g
= 40.767 %

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