COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 5, Problem 5QAP
To determine

(a)

The effect of weight of the book when reduce the applying force to the book in the same spot on the wall.

Expert Solution
Check Mark

Answer to Problem 5QAP

The weight of the book is not changed.

Explanation of Solution

Introduction:

The book is pressed against on the wall. When we reduce the applying force to the book, the book remains in the same spot on the wall.

COLLEGE PHYSICS, Chapter 5, Problem 5QAP , additional homework tip  1

W= Weight of the bookf = Frictional forceR = Force on book by wallF = Force exerted on wall by book

W=mg

So the magnitude remains constant. Therefore weight stays the same.

Conclusion:

The weight stays the same.

To determine

(b)

The effect of the normal force of the wall on the book when reduce the applying force to the book in the same spot on the wall.

Expert Solution
Check Mark

Answer to Problem 5QAP

The normal force of the wall on the book decreases.

Explanation of Solution

Introduction:

The book is pressed against on the wall. When we reduce the applying force to the book, the book remains in the same spot on the wall.

COLLEGE PHYSICS, Chapter 5, Problem 5QAP , additional homework tip  2

W= Weight of the bookf = Frictional forceR = Force on book by wallF = Force exerted on wall by book

R=F

When applied force is reduced the normal force decreases.

Conclusion:

The normal force of the wall on the book decreases.

To determine

(c)

The effect of the frictional force of the wall on the book when reduce the applying force to the book in the same spot on the wall.

Expert Solution
Check Mark

Answer to Problem 5QAP

The frictional force of the wall on the book is not changed.

Explanation of Solution

Introduction:

The book is pressed against on the wall. When we reduce the applying force to the book, the book remains in the same spot on the wall.

COLLEGE PHYSICS, Chapter 5, Problem 5QAP , additional homework tip  3

W= Weight of the bookf = Frictional forceR = Force on book by wallF = Force exerted on wall by book

f=W

So the weight of the book is constant. Therefore the frictional force of the wall on the book stays same.

Conclusion:

The frictional force of the wall on the book stays same.

To determine

(d)

The effect of the maximum static frictional force of the wall on the book when reduce the applying force to the book in the same spot on the wall.

Expert Solution
Check Mark

Answer to Problem 5QAP

The maximum static frictional force of the wall on the book deceases.

Explanation of Solution

Introduction:

The book is pressed against on the wall. When we reduce the applying force to the book, the book remains in the same spot on the wall.

COLLEGE PHYSICS, Chapter 5, Problem 5QAP , additional homework tip  4

W= Weight of the bookf = Frictional forceR = Force on book by wallF = Force exerted on wall by book

fmax=μR

When F reduces R decreases. Since μ is constant, fmax also decreases.

Conclusion:

The maximum static frictional force of the wall on the book deceases.

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Students have asked these similar questions
A 12 N horizontal force F pushes a block weighing 5.3 N against a vertical wall (see the figure). The coefficient of static friction between the wall and the block is 0.61, and the coefficient of kinetic friction is 0.48. Assume that the block is not moving initially. (a) Will the block move? ("yes" or "no") |(b) In unit-vector notation what is the force on the block from the wall?
A woman holds a book by placing it between her hands such that she presses at right angles to the front and back covers. The book has a mass of m = 1.7 kg and the coefficient of static friction between her hand and the book is μs = 0.59.   Force minimum?
a) A delivery truck with two stacked crates in the back brakes quickly. The crate on the bottom just barely stays put on the floor of the truck. Does the top crate stay put or does it fall off? The top crate has a mass of 27.0 kg and the mass of the bottom crate is 22.0 kg. The coefficient of static friction between the bottom crate and the truck is 0.420, and the coefficient of kinetic friction for that surface is 0.350. The coefficient of static friction between the crates is 0.400, and the coefficient of kinetic friction is 0.320. Hint: Don’t forget about Newton’s 3rd Law especially when dealing with friction between the two crates b) The top crate will slide off if it moves more than 87.5 cm. If the truck braked for 1.84 s did the top crate slide off? If not, how far did it move?

Chapter 5 Solutions

COLLEGE PHYSICS

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