Foundations of Materials Science and Engineering
Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 8.15, Problem 29AAP

Consider the binary peritectic iridium–osmium phase diagram of Figure P8.28. Make phase analyses of a 40 wt% Ir–60 wt% Os at the temperatures (a) 2600°C, (b) 2665°C + ΔT, (c) 2665°C − ΔT, and (d) 2800°C. Include in the phase analyses the four items listed in Problem 8.28.

Chapter 8.15, Problem 29AAP, Consider the binary peritectic iridiumosmium phase diagram of Figure P8.28. Make phase analyses of a

(a)

Expert Solution
Check Mark
To determine

Refer Fig P8.28, and perform a phase analysis of a 40 wt% Ir and 60 wt% Os at temperature of 2600°C.

Include the following in the phase analysis:

  1. i. The phase present.
  2. ii. The chemical composition of each phase.
  3. iii. The amount of every phase is available.
  4. iv. Draw the microstructure by the help of 2-cm-diameter circular fields.

Explanation of Solution

Refer Figure P8.28, and make a phase analysis at a temperature of 2600°C,

  1. i. Phases present or available are beta and alpha, that is β+α.
  2. ii. The chemical composition of Os in alpha phase is 42 wt% and in beta phase is 62.5 wt%.
  3. iii. Express the weight percentage of beta and alpha:

    wt%alpha=62.56062.542×100%=12.2%

    wt%beta=604262.542×100%=87.8%

Thus, the weight percentage of alpha and beta is 12.2wt%and87.8wt% respectively.

  1. iv. Show the microstructure as in Figure (1).

Foundations of Materials Science and Engineering, Chapter 8.15, Problem 29AAP , additional homework tip  1

(b)

Expert Solution
Check Mark
To determine

Repeat the same at 2665°C+ΔT.

Explanation of Solution

Refer Figure P8.28, and make a phase analysis at 2665°C+ΔT,

  1. i. Phases present or available are liquid and beta, that is L+β.
  2. ii. The chemical composition of Os in liquid phase is 23 wt% and in beta phase is 61.5 wt%.
  3. iii. Express the weight percentage of liquid and beta:

    wt%beta=602361.523×100%=96.1%

    wt%liquid=61.56061.523×100%=3.9%

Thus, the weight percentage of beta and liquid is 96.1wt%and3.9wt% respectively.

  1. iv. Show the microstructure as in Figure (2).

Foundations of Materials Science and Engineering, Chapter 8.15, Problem 29AAP , additional homework tip  2

(c)

Expert Solution
Check Mark
To determine

Repeat the same at 2665°CΔT.

Explanation of Solution

Refer Figure P8.28, and make a phase analysis at 2665°CΔT,

  1. i. Phases present or available are beta and alpha, that is β+α.
  2. ii. The chemical composition of Os in alpha phase is 43 wt% and in beta phase is 61.5 wt%.
  3. iii. Express the weight percentage of beta and alpha:

    wt%alpha=61.56061.543×100%=8.1%

    wt%beta=604361.543×100%=91.9%

Thus, the weight percentage of alpha and beta is 8.1wt%and91.9wt% respectively.

  1. iv. Show the microstructure as in Figure (3).

Foundations of Materials Science and Engineering, Chapter 8.15, Problem 29AAP , additional homework tip  3

(d)

Expert Solution
Check Mark
To determine

Repeat the same at 2800°C.

Explanation of Solution

Refer Figure P8.28, and make a phase analysis at a temperature of 2800°C,

  1. i. Phases present or available are beta and liquid, that is β+L.
  2. ii. The chemical composition of Os in liquid phase is 45 wt% and in beta phase is 85 wt%.
  3. iii. Express the weight percentage of liquid and beta:

    wt%liquid=85608545×100%=62.5%

    wt%beta=60458545×100%=37.5%

Thus, the weight percentage of liquid and beta is 62.5wt%and37.5wt% respectively.

  1. iv. Show the microstructure as in Figure (4).

Foundations of Materials Science and Engineering, Chapter 8.15, Problem 29AAP , additional homework tip  4

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Foundations of Materials Science and Engineering

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